Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 18:40Z

F = ma

∑_{k=1}^{n} k = n(n+1)/2

273K

∑_{k=1}^{n} k = n(n+1)/2

263K

8γ² + 7γ + 3 = 0

d/dt [t^3] = 3t^2

139K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

108K

N₂ + 3H₂ ⇌ 2NH₃

∑_{k=1}^{n} k = n(n+1)/2

333K

det| 9 4 ; 1 10 | = 86

160K

e^{i\pi} + 1 = 0

439K

∑_{k=1}^{n} k = n(n+1)/2

413K

∫₀^∞ e^(-x²) dx = √π / 2

297K