Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:49Z

10y² + 2y + 6 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

5z² + 8z + 3 = 0

438K

∫₀^∞ e^(-t²) dt = √π / 2

∑_{k=1}^{n} k = n(n+1)/2

186K

∇ × E = −∂B/∂t

411K

e^{i\pi} + 1 = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

448K

det| 7 4 ; 4 8 | = 40

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det| 3 1 ; 7 4 | = 5

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\lim_{r\to 0} \frac{\sin r}{r} = 1

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F = G m₁m₂ / r²

181K

N₂ + 3H₂ ⇌ 2NH₃

80K