Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 20:57Z
det| 6 5 ; 4 7 | = 22
det| 9 4 ; 1 10 | = 86
460K
∫₀^∞ e^(-t²) dt = √π / 2
438K
∇²φ = 0
\frac{9}{2} \sum_{i=1}^{n} i^{2}
det| 4 7 ; 2 5 | = 6
448K
F = ma
det| 4 8 ; 3 5 | = -4
459K
ΔS ≥ 0
ΔS ≥ 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∇²γ = 0
1φ² + 4φ + 5 = 0