Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 17:07Z

det| 11 2 ; 2 12 | = 128

d/dt [t^3] = 3t^2

460K

∇ × E = −∂B/∂t

438K

CaCO₃ → CaO + CO₂

8ψ² + 7ψ + 0 = 0

186K

e^{i\pi} + 1 = 0

411K

3θ² + 7θ + 1 = 0

det| 11 5 ; 0 12 | = 132

448K

\frac{2}{2} \sum_{i=1}^{n} i^{2}

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

\lim_{β\to 0} \frac{\sin β}{β} = 1

459K

∇²z = 0

406K

2H₂ + O₂ → 2H₂O

∇ × E = −∂B/∂t

∫₀^∞ e^(-z²) dz = √π / 2