Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:21Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

det| 5 6 ; 2 6 | = 18

438K

∫₀^∞ e^(-x²) dx = √π / 2

λ = h/p

186K

\lim_{r\to 0} \frac{\sin r}{r} = 1

411K

4φ² + 6φ + 2 = 0

CH₄ + 2O₂ → CO₂ + 2H₂O

448K

e^{i\pi} + 1 = 0

22K

∑_{k=1}^{n} k = n(n+1)/2

459K

d/dt [t^3] = 3t^2

406K

N₂ + 3H₂ ⇌ 2NH₃

181K

det| 12 1 ; 5 13 | = 151

80K

det| 9 4 ; 1 10 | = 86

359K

det| 4 2 ; 6 5 | = 8

455K