Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:57Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

e^{i\pi} + 1 = 0

438K

∫₀^∞ e^(-x²) dx = √π / 2

det| 5 2 ; 3 6 | = 24

186K

10γ² + 8γ + 7 = 0

411K

4φ² + 6φ + 2 = 0

∑_{k=1}^{n} k = n(n+1)/2

448K

7y² + 9y + 1 = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

\lim_{γ\to 0} \frac{\sin γ}{γ} = 1

459K

e^{i\pi} + 1 = 0

406K

∇²ω = 0

det| 7 4 ; 4 8 | = 40

181K

∂γ/∂θ = 2γ

80K

N₂ + 3H₂ ⇌ 2NH₃

359K