Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:33Z

∇²t = 0

ΔS ≥ 0

460K

∫₀^∞ e^(-z²) dz = √π / 2

438K

det| 6 4 ; 3 7 | = 30

iħ ∂ψ/∂t = Ĥψ

186K

8ψ² + 7ψ + 0 = 0

411K

ΔS ≥ 0

det| 3 1 ; 7 4 | = 5

448K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

22K

1z² + 3z + 2 = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

459K

N₂ + 3H₂ ⇌ 2NH₃

406K

3z² + 5z + 1 = 0

181K

det| 1 4 ; 3 2 | = -10

80K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

359K

10ω² + 7ω + 4 = 0

455K