Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:57Z

10γ² + 4γ + 3 = 0

\lim_{r\to 0} \frac{\sin r}{r} = 1

460K

E = mc²

438K

d/dβ [β^11] = 11β^10

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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∑_{k=1}^{n} k = n(n+1)/2

411K

3x² + 4x + 6 = 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

448K

F = G m₁m₂ / r²

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CaCO₃ → CaO + CO₂

iħ ∂ψ/∂t = Ĥψ

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e^{i\pi} + 1 = 0

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Fe₂O₃ + 3CO → 2Fe + 3CO₂

∫₀^∞ e^(-α²) dα = √π / 2

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det| 9 4 ; 1 10 | = 86

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