Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 02:08Z

Fe₂O₃ + 3CO → 2Fe + 3CO₂

e^{i\pi} + 1 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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\frac{8}{4} \sum_{i=1}^{n} i^{2}

N₂ + 3H₂ ⇌ 2NH₃

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Fe₂O₃ + 3CO → 2Fe + 3CO₂

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N₂ + 3H₂ ⇌ 2NH₃

det| 7 4 ; 4 8 | = 40

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\lim_{t\to 0} \frac{\sin t}{t} = 1

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4t² + 3t + 3 = 0

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7r² + 8r + 5 = 0

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∫₀^∞ e^(-θ²) dθ = √π / 2

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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iħ ∂ψ/∂t = Ĥψ

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