Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:37Z

11n² + 5n + 4 = 0

PV = nRT

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

F = G m₁m₂ / r²

186K

2H₂ + O₂ → 2H₂O

411K

4φ² + 6φ + 2 = 0

∑_{k=1}^{n} k = n(n+1)/2

448K

det| 7 4 ; 4 8 | = 40

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

\lim_{β\to 0} \frac{\sin β}{β} = 1

459K

det| 12 1 ; 5 13 | = 151

406K

∇²ω = 0

∇ × E = −∂B/∂t

181K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

80K

d/dr [r^2] = 2r^1

PV = nRT

359K

ΔS ≥ 0