Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 02:04Z

Fe₂O₃ + 3CO → 2Fe + 3CO₂

∇ × E = −∂B/∂t

451K

∂y/∂n = 5y

264K

\frac{8}{4} \sum_{i=1}^{n} i^{2}

∂n/∂θ = 3n

297K

iħ ∂ψ/∂t = Ĥψ

252K

N₂ + 3H₂ ⇌ 2NH₃

8θ² + 8θ + 6 = 0

48K

8ψ² + 7ψ + 0 = 0

411K

2α² + 3α + 3 = 0

d/dt [t^3] = 3t^2

377K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

299K

det| 10 7 ; 6 11 | = 68

det| 3 7 ; 2 4 | = -2

401K

∑_{k=1}^{n} k = n(n+1)/2

420K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

109K

1n² + 7n + 3 = 0

184K