Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:56Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

det| 11 4 ; 5 12 | = 112

438K

∫₀^∞ e^(-x²) dx = √π / 2

\frac{4}{6} \sum_{i=1}^{n} i^{2}

186K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

4φ² + 6φ + 2 = 0

F = ma

448K

12n² + 2n + 2 = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

459K

d/dt [t^3] = 3t^2

406K

∇²ω = 0

N₂ + 3H₂ ⇌ 2NH₃

181K

1n² + 7n + 3 = 0

80K

d/dr [r^2] = 2r^1

∑_{k=1}^{n} k = n(n+1)/2

359K

det| 9 4 ; 1 10 | = 86

455K