Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 22:37Z

3n² + 7n + 7 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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∫₀^∞ e^(-ω²) dω = √π / 2

iħ ∂ψ/∂t = Ĥψ

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\lim_{t\to 0} \frac{\sin t}{t} = 1

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\frac{10}{6} \sum_{i=1}^{n} i^{2}

∑_{k=1}^{n} k = n(n+1)/2

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F = G m₁m₂ / r²

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d/dr [r^12] = 12r^11

6n² + 7n + 6 = 0

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8x² + 2x + 7 = 0

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d/dφ [φ^5] = 5φ^4

1θ² + 2θ + 6 = 0

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det| 9 4 ; 1 10 | = 86

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2H₂ + O₂ → 2H₂O