Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:37Z

3γ² + 8γ + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

d/dt [t^3] = 3t^2

438K

PV = nRT

∫₀^∞ e^(-α²) dα = √π / 2

186K

\frac{2}{2} \sum_{i=1}^{n} i^{2}

411K

det| 1 9 ; 5 2 | = -43

ω = 2πf

448K

det| 9 4 ; 1 10 | = 86

22K

ω = 2πf

4γ² + 1γ + 7 = 0

459K

∂z/∂φ = 7z

406K

∂n/∂ψ = 6n

∑_{k=1}^{n} k = n(n+1)/2

181K

F = G m₁m₂ / r²

80K

N₂ + 3H₂ ⇌ 2NH₃