Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:21Z

∇²n = 0

∇ × E = −∂B/∂t

273K

det| 5 2 ; 3 6 | = 24

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9r² + 4r + 1 = 0

ω = 2πf

139K

∑_{k=1}^{n} k = n(n+1)/2

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∫₀^∞ e^(-t²) dt = √π / 2

333K

8ψ² + 7ψ + 0 = 0

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11γ² + 3γ + 6 = 0

d/dt [t^3] = 3t^2

439K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

413K

\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1

det| 3 7 ; 2 4 | = -2

297K

∑_{k=1}^{n} k = n(n+1)/2

128K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

404K

∫₀^∞ e^(-θ²) dθ = √π / 2

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