Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 06:01Z

9φ² + 5φ + 2 = 0

∑_{k=1}^{n} k = n(n+1)/2

451K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

264K

ω = 2πf

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

297K

det| 11 9 ; 0 12 | = 132

252K

2β² + 4β + 2 = 0

∑_{k=1}^{n} k = n(n+1)/2

48K

det| 3 6 ; 0 4 | = 12

411K

ω = 2πf

det| 7 4 ; 4 8 | = 40

377K

\frac{4}{9} \sum_{i=1}^{n} i^{2}

299K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

401K

det| 10 2 ; 3 11 | = 104

420K

N₂ + 3H₂ ⇌ 2NH₃

109K