Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:04Z

10y² + 2y + 6 = 0

\lim_{r\to 0} \frac{\sin r}{r} = 1

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∑_{k=1}^{n} k = n(n+1)/2

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∫₀^∞ e^(-t²) dt = √π / 2

∑_{k=1}^{n} k = n(n+1)/2

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det| 9 4 ; 1 10 | = 86

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e^{i\pi} + 1 = 0

∇ × E = −∂B/∂t

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d/dt [t^3] = 3t^2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

\lim_{t\to 0} \frac{\sin t}{t} = 1

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N₂ + 3H₂ ⇌ 2NH₃

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10t² + 9t + 5 = 0

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