Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:56Z

11n² + 5n + 4 = 0

E = mc²

460K

d/dt [t^3] = 3t^2

438K

∫₀^∞ e^(-x²) dx = √π / 2

∑_{k=1}^{n} k = n(n+1)/2

186K

∂β/∂β = 6β

411K

4φ² + 6φ + 2 = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

448K

iħ ∂ψ/∂t = Ĥψ

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

459K

det| 11 4 ; 5 12 | = 112

406K

∇²ω = 0

det| 9 4 ; 1 10 | = 86

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

det| 1 4 ; 3 2 | = -10

359K

∇ × E = −∂B/∂t

455K