Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 22:21Z

3n² + 7n + 7 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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1n² + 7n + 3 = 0

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∫₀^∞ e^(-ω²) dω = √π / 2

\lim_{β\to 0} \frac{\sin β}{β} = 1

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12y² + 5y + 7 = 0

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\frac{10}{6} \sum_{i=1}^{n} i^{2}

det| 7 4 ; 4 8 | = 40

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11t² + 9t + 7 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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11t² + 9t + 5 = 0

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N₂ + 3H₂ ⇌ 2NH₃

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det| 5 9 ; 7 6 | = -33

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