Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-19 19:06Z
\frac{11}{4} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
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d/dx [x^3] = 3x^2
\frac{12}{8} \sum_{i=1}^{n} i^{2}
det| 11 4 ; 5 12 | = 112
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∑_{k=1}^{n} k = n(n+1)/2
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det| 9 4 ; 1 10 | = 86
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det| 5 9 ; 7 6 | = -33
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