Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 12:20Z

∑_{k=1}^{n} k = n(n+1)/2

d/dφ [φ^1] = 1φ^0

460K

2H₂ + O₂ → 2H₂O

438K

4y² + 7y + 7 = 0

E = mc²

186K

∂ψ/∂β = 3ψ

411K

∇²t = 0

F = G m₁m₂ / r²

448K

4γ² + 1γ + 7 = 0

22K

6β² + 2β + 2 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

459K

det| 12 6 ; 0 13 | = 156

406K

2φ² + 2φ + 5 = 0

∫₀^∞ e^(-t²) dt = √π / 2

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

det| 5 2 ; 6 6 | = 18

359K

det| 7 8 ; 4 8 | = 24

455K

2x² + 6x + 2 = 0

191K