Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 02:50Z

det| 5 4 ; 6 6 | = 6

10β² + 4β + 1 = 0

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∇²r = 0

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∇²φ = 0

∫₀^∞ e^(-t²) dt = √π / 2

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∇²ω = 0

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det| 12 5 ; 4 13 | = 136

8ψ² + 7ψ + 0 = 0

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2H₂ + O₂ → 2H₂O

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∑_{k=1}^{n} k = n(n+1)/2

N₂ + 3H₂ ⇌ 2NH₃

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∫₀^∞ e^(-θ²) dθ = √π / 2

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\oint_C \vec{F}\cdot d\vec{r} = 0

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det| 7 8 ; 4 8 | = 24

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iħ ∂ψ/∂t = Ĥψ

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N₂ + 3H₂ ⇌ 2NH₃

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