Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 00:43Z

d/dy [y^8] = 8y^7

∫₀^∞ e^(-θ²) dθ = √π / 2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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\lim_{x\to 0} \frac{\sin x}{x} = 1

det| 3 7 ; 2 4 | = -2

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iħ ∂ψ/∂t = Ĥψ

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d/dn [n^3] = 3n^2

N₂ + 3H₂ ⇌ 2NH₃

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ω = 2πf

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6t² + 4t + 0 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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det| 3 6 ; 0 4 | = 12

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N₂ + 3H₂ ⇌ 2NH₃

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e^{i\pi} + 1 = 0

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8ψ² + 7ψ + 0 = 0

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