Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:38Z

10y² + 2y + 6 = 0

det| 7 4 ; 4 8 | = 40

460K

N₂ + 3H₂ ⇌ 2NH₃

438K

∫₀^∞ e^(-t²) dt = √π / 2

∑_{k=1}^{n} k = n(n+1)/2

186K

∫₀^∞ e^(-t²) dt = √π / 2

411K

e^{i\pi} + 1 = 0

det| 4 8 ; 3 5 | = -4

448K

\frac{2}{2} \sum_{i=1}^{n} i^{2}

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∂y/∂n = 5y

459K

iħ ∂ψ/∂t = Ĥψ

406K

λ = h/p

iħ ∂ψ/∂t = Ĥψ

d/dγ [γ^3] = 3γ^2