Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:16Z

11n² + 5n + 4 = 0

det| 9 8 ; 3 10 | = 66

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

11t² + 9t + 5 = 0

186K

\lim_{r\to 0} \frac{\sin r}{r} = 1

411K

4φ² + 6φ + 2 = 0

det| 5 9 ; 7 6 | = -33

448K

∇ × E = −∂B/∂t

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

det| 5 2 ; 3 6 | = 24

459K

d/dt [t^3] = 3t^2

406K

∇²ω = 0

8ψ² + 7ψ + 0 = 0

181K

d/dα [α^3] = 3α^2

d/dr [r^2] = 2r^1

ΔS ≥ 0

8β² + 5β + 0 = 0