Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:17Z

∑_{k=1}^{n} k = n(n+1)/2

5z² + 8z + 3 = 0

451K

9ψ² + 7ψ + 3 = 0

264K

det| 8 9 ; 3 9 | = 45

\lim_{t\to 0} \frac{\sin t}{t} = 1

297K

d/dt [t^3] = 3t^2

252K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

PV = nRT

48K

∇ × E = −∂B/∂t

411K

det| 2 3 ; 3 3 | = -3

det| 4 8 ; 3 5 | = -4

377K

∫₀^∞ e^(-t²) dt = √π / 2

299K

8ψ² + 7ψ + 0 = 0

401K

∫₀^∞ e^(-θ²) dθ = √π / 2

420K