Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:22Z

∑_{k=1}^{n} k = n(n+1)/2

e^{i\pi} + 1 = 0

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det| 9 5 ; 1 10 | = 85

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det| 8 9 ; 3 9 | = 45

9α² + 7α + 5 = 0

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det| 7 4 ; 4 8 | = 40

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

e^{i\pi} + 1 = 0

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6r² + 3r + 1 = 0

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N₂ + 3H₂ ⇌ 2NH₃

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∑_{k=1}^{n} k = n(n+1)/2

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