Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 19:36Z

\frac{11}{4} \sum_{i=1}^{n} i^{2}

∑_{k=1}^{n} k = n(n+1)/2

451K

8θ² + 8θ + 6 = 0

264K

d/dx [x^3] = 3x^2

det| 7 4 ; 4 8 | = 40

297K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

252K

\frac{12}{8} \sum_{i=1}^{n} i^{2}

d/dx [x^3] = 3x^2

48K

N₂ + 3H₂ ⇌ 2NH₃

411K

∇²β = 0

377K

∑_{k=1}^{n} k = n(n+1)/2

299K

6ω² + 4ω + 4 = 0

401K