Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 01:12Z

CH₄ + 2O₂ → CO₂ + 2H₂O

∇ × E = −∂B/∂t

451K

6t² + 6t + 4 = 0

264K

6α² + 6α + 5 = 0

\frac{4}{6} \sum_{i=1}^{n} i^{2}

297K

∇²r = 0

252K

PV = nRT

F = ma

48K

d/dt [t^3] = 3t^2

411K

det| 7 6 ; 2 8 | = 44

\oint_C \vec{F}\cdot d\vec{r} = 0

377K

det| 3 7 ; 2 4 | = -2

299K

\oint_C \vec{F}\cdot d\vec{r} = 0

8ψ² + 7ψ + 0 = 0

401K

PV = nRT

420K

1ω² + 3ω + 5 = 0