Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:23Z
∇²n = 0
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
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9r² + 4r + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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\lim_{t\to 0} \frac{\sin t}{t} = 1
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11γ² + 3γ + 6 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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det| 2 3 ; 5 3 | = -9
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det| 9 4 ; 1 10 | = 86
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