Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:32Z

∇²t = 0

det| 7 4 ; 4 8 | = 40

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

438K

det| 6 4 ; 3 7 | = 30

∇ × E = −∂B/∂t

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6t² + 6t + 4 = 0

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ΔS ≥ 0

det| 2 3 ; 5 3 | = -9

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∫₀^∞ e^(-θ²) dθ = √π / 2

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1z² + 3z + 2 = 0

λ = h/p

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CH₄ + 2O₂ → CO₂ + 2H₂O

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7t² + 3t + 1 = 0

F = G m₁m₂ / r²

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det| 11 5 ; 2 12 | = 122

det| 8 3 ; 4 9 | = 60

10γ² + 8γ + 2 = 0

∇ × E = −∂B/∂t

λ = h/p