Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 02:33Z

Fe₂O₃ + 3CO → 2Fe + 3CO₂

d/dt [t^3] = 3t^2

451K

∇ × E = −∂B/∂t

264K

\frac{8}{4} \sum_{i=1}^{n} i^{2}

d/dx [x^3] = 3x^2

297K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

252K

N₂ + 3H₂ ⇌ 2NH₃

6t² + 6t + 4 = 0

48K

∑_{k=1}^{n} k = n(n+1)/2

411K

2α² + 3α + 3 = 0

det| 1 4 ; 3 2 | = -10

377K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

299K

det| 10 7 ; 6 11 | = 68

8ψ² + 7ψ + 0 = 0

401K

6n² + 5n + 2 = 0

7γ² + 1γ + 1 = 0

2x² + 3x + 3 = 0