Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:37Z

11n² + 5n + 4 = 0

e^{i\pi} + 1 = 0

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

Fe₂O₃ + 3CO → 2Fe + 3CO₂

186K

det| 7 4 ; 4 8 | = 40

411K

4φ² + 6φ + 2 = 0

PV = nRT

448K

E = mc²

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

459K

det| 3 6 ; 0 4 | = 12

406K

∇ × E = −∂B/∂t

181K

∂z/∂φ = 7z

80K

F = G m₁m₂ / r²

359K