Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:18Z

∇²n = 0

10β² + 4β + 1 = 0

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\frac{4}{6} \sum_{i=1}^{n} i^{2}

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9r² + 4r + 1 = 0

∑_{k=1}^{n} k = n(n+1)/2

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iħ ∂ψ/∂t = Ĥψ

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∑_{k=1}^{n} k = n(n+1)/2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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11γ² + 3γ + 6 = 0

N₂ + 3H₂ ⇌ 2NH₃

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∫₀^∞ e^(-θ²) dθ = √π / 2

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\lim_{t\to 0} \frac{\sin t}{t} = 1

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det| 11 9 ; 0 12 | = 132

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det| 7 4 ; 4 8 | = 40

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det| 1 4 ; 3 2 | = -10

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