Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:50Z

3γ² + 8γ + 4 = 0

d/dt [t^3] = 3t^2

460K

∇ × E = −∂B/∂t

438K

PV = nRT

8ψ² + 7ψ + 0 = 0

186K

8θ² + 8θ + 6 = 0

411K

det| 1 9 ; 5 2 | = -43

det| 4 8 ; 3 5 | = -4

448K

\frac{2}{2} \sum_{i=1}^{n} i^{2}

22K

ω = 2πf

det| 3 6 ; 0 4 | = 12

459K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

∂n/∂ψ = 6n

∫₀^∞ e^(-ψ²) dψ = √π / 2

N₂ + 3H₂ ⇌ 2NH₃