Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:59Z

10y² + 2y + 6 = 0

N₂ + 3H₂ ⇌ 2NH₃

460K

8ψ² + 7ψ + 0 = 0

438K

∫₀^∞ e^(-t²) dt = √π / 2

∇²r = 0

186K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

e^{i\pi} + 1 = 0

\lim_{t\to 0} \frac{\sin t}{t} = 1

448K

det| 9 8 ; 3 10 | = 66

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

e^{i\pi} + 1 = 0

459K

det| 8 9 ; 4 9 | = 36

406K

iħ ∂ψ/∂t = Ĥψ

181K

F = G m₁m₂ / r²

80K

iħ ∂ψ/∂t = Ĥψ

359K

∫₀^∞ e^(-x²) dx = √π / 2

455K