Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:17Z

11n² + 5n + 4 = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-x²) dx = √π / 2

N₂ + 3H₂ ⇌ 2NH₃

186K

CaCO₃ → CaO + CO₂

411K

4φ² + 6φ + 2 = 0

det| 7 4 ; 4 8 | = 40

448K

2H₂ + O₂ → 2H₂O

22K

4t² + 3t + 3 = 0

459K

N₂ + 3H₂ ⇌ 2NH₃

406K

CH₄ + 2O₂ → CO₂ + 2H₂O

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

E = mc²

359K