Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:47Z

∇²n = 0

E = mc²

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N₂ + 3H₂ ⇌ 2NH₃

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9r² + 4r + 1 = 0

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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det| 4 7 ; 2 5 | = 6

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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∫₀^∞ e^(-θ²) dθ = √π / 2

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11γ² + 3γ + 6 = 0

8ψ² + 7ψ + 0 = 0

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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iħ ∂ψ/∂t = Ĥψ

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