Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 12:36Z
∑_{k=1}^{n} k = n(n+1)/2
det| 5 6 ; 2 6 | = 18
438K
4y² + 7y + 7 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
411K
∇²t = 0
∑_{k=1}^{n} k = n(n+1)/2
22K
6β² + 2β + 2 = 0
2φ² + 2φ + 5 = 0
5α² + 7α + 6 = 0
\lim_{n\to 0} \frac{\sin n}{n} = 1
det| 7 8 ; 0 8 | = 56