Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:48Z

∇²n = 0

∇ × E = −∂B/∂t

273K

E = mc²

263K

9r² + 4r + 1 = 0

\frac{4}{6} \sum_{i=1}^{n} i^{2}

139K

iħ ∂ψ/∂t = Ĥψ

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

det| 5 6 ; 2 6 | = 18

333K

d/dt [t^3] = 3t^2

160K

11γ² + 3γ + 6 = 0

N₂ + 3H₂ ⇌ 2NH₃

439K

∑_{k=1}^{n} k = n(n+1)/2

413K

\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1

8ψ² + 7ψ + 0 = 0

297K

e^{i\pi} + 1 = 0

128K

det| 6 1 ; 3 7 | = 39