Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:48Z
∇²n = 0
∫₀^∞ e^(-θ²) dθ = √π / 2
273K
9r² + 4r + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
333K
11γ² + 3γ + 6 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
439K
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
∫₀^∞ e^(-ψ²) dψ = √π / 2
128K
det| 9 4 ; 1 10 | = 86
404K