Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:43Z

∇²t = 0

det| 7 8 ; 4 8 | = 24

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∫₀^∞ e^(-z²) dz = √π / 2

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det| 6 4 ; 3 7 | = 30

d/dt [t^3] = 3t^2

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8ψ² + 7ψ + 0 = 0

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ΔS ≥ 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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∂α/∂ω = 3α

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1z² + 3z + 2 = 0

det| 11 5 ; 0 12 | = 132

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∇ × E = −∂B/∂t

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\frac{4}{6} \sum_{i=1}^{n} i^{2}

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d/dφ [φ^1] = 1φ^0

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N₂ + 3H₂ ⇌ 2NH₃

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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