Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 20:36Z

∑_{k=1}^{n} k = n(n+1)/2

∇ × E = −∂B/∂t

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2H₂ + O₂ → 2H₂O

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det| 8 9 ; 3 9 | = 45

det| 11 4 ; 5 12 | = 112

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∑_{k=1}^{n} k = n(n+1)/2

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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2H₂ + O₂ → 2H₂O

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8ψ² + 7ψ + 0 = 0

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det| 5 2 ; 3 6 | = 24

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d/dt [t^3] = 3t^2

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det| 9 5 ; 1 10 | = 85

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8x² + 2x + 7 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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