Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 02:20Z

Fe₂O₃ + 3CO → 2Fe + 3CO₂

4t² + 3t + 3 = 0

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\frac{2}{2} \sum_{i=1}^{n} i^{2}

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\frac{8}{4} \sum_{i=1}^{n} i^{2}

d/dt [t^3] = 3t^2

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1θ² + 2θ + 6 = 0

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N₂ + 3H₂ ⇌ 2NH₃

∂y/∂n = 5y

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Fe₂O₃ + 3CO → 2Fe + 3CO₂

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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∇ × E = −∂B/∂t

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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∫₀^∞ e^(-t²) dt = √π / 2

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8ψ² + 7ψ + 0 = 0

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2H₂ + O₂ → 2H₂O

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