Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 02:20Z

Fe₂O₃ + 3CO → 2Fe + 3CO₂

det| 3 1 ; 7 4 | = 5

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∇ × E = −∂B/∂t

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\frac{8}{4} \sum_{i=1}^{n} i^{2}

\lim_{t\to 0} \frac{\sin t}{t} = 1

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10t² + 9t + 5 = 0

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N₂ + 3H₂ ⇌ 2NH₃

d/dt [t^3] = 3t^2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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2α² + 3α + 3 = 0

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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8ψ² + 7ψ + 0 = 0

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9α² + 7α + 5 = 0

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8x² + 2x + 7 = 0

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