Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:32Z

∇²t = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

438K

det| 6 4 ; 3 7 | = 30

∂ψ/∂β = 3ψ

186K

∇²t = 0

411K

ΔS ≥ 0

F = ma

448K

ω = 2πf

22K

1z² + 3z + 2 = 0

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

459K

d/dt [t^3] = 3t^2

406K

7t² + 3t + 1 = 0

∂y/∂n = 5y

181K

∂γ/∂θ = 2γ

80K

det| 8 3 ; 4 9 | = 60

det| 7 9 ; 1 8 | = 47

359K

det| 9 4 ; 1 10 | = 86

455K