Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:31Z

11n² + 5n + 4 = 0

N₂ + 3H₂ ⇌ 2NH₃

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-x²) dx = √π / 2

Fe₂O₃ + 3CO → 2Fe + 3CO₂

186K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

411K

4φ² + 6φ + 2 = 0

\lim_{t\to 0} \frac{\sin t}{t} = 1

448K

∑_{k=1}^{n} k = n(n+1)/2

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

e^{i\pi} + 1 = 0

459K

ΔS ≥ 0

406K

∂α/∂ω = 3α

181K

8x² + 2x + 7 = 0

80K

det| 7 4 ; 4 8 | = 40

359K

N₂ + 3H₂ ⇌ 2NH₃

455K