Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:26Z

11n² + 5n + 4 = 0

F = G m₁m₂ / r²

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

\oint_C \vec{F}\cdot d\vec{r} = 0

186K

d/dt [t^3] = 3t^2

411K

4φ² + 6φ + 2 = 0

PV = nRT

448K

∂α/∂ω = 3α

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

\lim_{t\to 0} \frac{\sin t}{t} = 1

459K

7r² + 8r + 5 = 0

406K

det| 9 4 ; 1 10 | = 86

181K

N₂ + 3H₂ ⇌ 2NH₃

80K

∑_{k=1}^{n} k = n(n+1)/2

359K