Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 11:35Z

∇²t = 0

8ψ² + 7ψ + 0 = 0

460K

det| 1 4 ; 3 2 | = -10

438K

det| 6 4 ; 3 7 | = 30

det| 7 8 ; 4 8 | = 24

186K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

411K

ΔS ≥ 0

∑_{k=1}^{n} k = n(n+1)/2

448K

det| 12 2 ; 2 13 | = 152

22K

1z² + 3z + 2 = 0

∇ × E = −∂B/∂t

459K

d/dt [t^3] = 3t^2

406K

7t² + 3t + 1 = 0

∑_{k=1}^{n} k = n(n+1)/2

181K

det| 10 7 ; 3 11 | = 89

80K

N₂ + 3H₂ ⇌ 2NH₃

359K