Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 02:49Z
det| 5 4 ; 6 6 | = 6
det| 3 1 ; 7 4 | = 5
438K
∇²φ = 0
det| 7 4 ; 4 8 | = 40
186K
det| 11 5 ; 0 12 | = 132
411K
det| 12 5 ; 4 13 | = 136
∑_{k=1}^{n} k = n(n+1)/2
22K
∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
459K
CH₄ + 2O₂ → CO₂ + 2H₂O
406K
CaCO₃ → CaO + CO₂
ω = 2πf